Base | Representation |
---|---|
bin | 10001101001111111100… |
… | …000100010101001101111 |
3 | 11021222210100122221201212 |
4 | 101221333200202221233 |
5 | 124334334410430242 |
6 | 2325220322425035 |
7 | 153442125646262 |
oct | 21517740425157 |
9 | 4258710587655 |
10 | 1213320014447 |
11 | 4286255760a2 |
12 | 17719650217b |
13 | 8a553074368 |
14 | 42a21596cd9 |
15 | 218642a1782 |
hex | 11a7f822a6f |
1213320014447 has 2 divisors, whose sum is σ = 1213320014448. Its totient is φ = 1213320014446.
The previous prime is 1213320014381. The next prime is 1213320014453. The reversal of 1213320014447 is 7444100233121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1213320014447 - 226 = 1213252905583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213320014947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606660007223 + 606660007224.
It is an arithmetic number, because the mean of its divisors is an integer number (606660007224).
Almost surely, 21213320014447 is an apocalyptic number.
1213320014447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213320014447 is an equidigital number, since it uses as much as digits as its factorization.
1213320014447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1213320014447 its reverse (7444100233121), we get a palindrome (8657420247568).
The spelling of 1213320014447 in words is "one trillion, two hundred thirteen billion, three hundred twenty million, fourteen thousand, four hundred forty-seven".
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