Base | Representation |
---|---|
bin | 1011000010010000000111… |
… | …0001010011011111101011 |
3 | 1120221221012101201022002111 |
4 | 2300210001301103133223 |
5 | 3042243010423011243 |
6 | 41445544451343151 |
7 | 2361413534665015 |
oct | 260440161233753 |
9 | 46857171638074 |
10 | 12133312313323 |
11 | 3958788538a63 |
12 | 143b6258b1ab7 |
13 | 6a0221898216 |
14 | 2dd380d4b1b5 |
15 | 16093696a39d |
hex | b0901c537eb |
12133312313323 has 2 divisors, whose sum is σ = 12133312313324. Its totient is φ = 12133312313322.
The previous prime is 12133312313321. The next prime is 12133312313327. The reversal of 12133312313323 is 32331321333121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12133312313323 - 21 = 12133312313321 is a prime.
Together with 12133312313321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12133312313321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066656156661 + 6066656156662.
It is an arithmetic number, because the mean of its divisors is an integer number (6066656156662).
Almost surely, 212133312313323 is an apocalyptic number.
12133312313323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133312313323 is an equidigital number, since it uses as much as digits as its factorization.
12133312313323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17496, while the sum is 31.
Adding to 12133312313323 its reverse (32331321333121), we get a palindrome (44464633646444).
The spelling of 12133312313323 in words is "twelve trillion, one hundred thirty-three billion, three hundred twelve million, three hundred thirteen thousand, three hundred twenty-three".
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