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121334342211149 is a prime number
BaseRepresentation
bin11011100101101001011010…
…010111011101011001001101
3120220121110010221001120102212
4123211221122113131121031
5111400420213101224044
61110020121033200205
734362055052635244
oct3345513227353115
9526543127046385
10121334342211149
113572a672aa8991
12117374a9860065
135291a193977c2
1421d688361795b
15e062b84c5a9e
hex6e5a5a5dd64d

121334342211149 has 2 divisors, whose sum is σ = 121334342211150. Its totient is φ = 121334342211148.

The previous prime is 121334342211023. The next prime is 121334342211151. The reversal of 121334342211149 is 941112243433121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95384385519049 + 25949956692100 = 9766493^2 + 5094110^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121334342211149 is a prime.

Together with 121334342211151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121334342210149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60667171105574 + 60667171105575.

It is an arithmetic number, because the mean of its divisors is an integer number (60667171105575).

Almost surely, 2121334342211149 is an apocalyptic number.

It is an amenable number.

121334342211149 is a deficient number, since it is larger than the sum of its proper divisors (1).

121334342211149 is an equidigital number, since it uses as much as digits as its factorization.

121334342211149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 124416, while the sum is 41.

The spelling of 121334342211149 in words is "one hundred twenty-one trillion, three hundred thirty-four billion, three hundred forty-two million, two hundred eleven thousand, one hundred forty-nine".