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12133445352013 is a prime number
BaseRepresentation
bin1011000010010000100110…
…1100110011101001001101
31120221221112200001100212101
42300210021230303221031
53042243244002231023
641450010003035101
72361420041542636
oct260441154635115
946857480040771
1012133445352013
113958846645997
12143b66236ba91
136a0243308b3b
142dd39489c88d
151609434991ad
hexb0909b33a4d

12133445352013 has 2 divisors, whose sum is σ = 12133445352014. Its totient is φ = 12133445352012.

The previous prime is 12133445351999. The next prime is 12133445352037. The reversal of 12133445352013 is 31025354433121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6503203819044 + 5630241532969 = 2550138^2 + 2372813^2 .

It is a cyclic number.

It is not a de Polignac number, because 12133445352013 - 213 = 12133445343821 is a prime.

It is a super-2 number, since 2×121334453520132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12133445352053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066722676006 + 6066722676007.

It is an arithmetic number, because the mean of its divisors is an integer number (6066722676007).

Almost surely, 212133445352013 is an apocalyptic number.

It is an amenable number.

12133445352013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12133445352013 is an equidigital number, since it uses as much as digits as its factorization.

12133445352013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 12133445352013 its reverse (31025354433121), we get a palindrome (43158799785134).

The spelling of 12133445352013 in words is "twelve trillion, one hundred thirty-three billion, four hundred forty-five million, three hundred fifty-two thousand, thirteen".