121340115341 has 2 divisors, whose sum is σ = 121340115342. Its totient is φ = 121340115340.

The previous prime is 121340115289. The next prime is 121340115343. The reversal of 121340115341 is 143511043121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118867042441 + 2473072900 = 344771^2 + 49730^2 .

It is an emirp because it is prime and its reverse (143511043121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121340115341 is a prime.

Together with 121340115343, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121340115341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121340115343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60670057670 + 60670057671.

It is an arithmetic number, because the mean of its divisors is an integer number (60670057671).

Almost surely, 2^121340115341 is an apocalyptic number.

It is an amenable number.

121340115341 is a deficient number, since it is larger than the sum of its proper divisors (1).

121340115341 is an equidigital number, since it uses as much as digits as its factorization.

121340115341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 121340115341 its reverse (143511043121), we get a palindrome (264851158462).

The spelling of 121340115341 in words is "one hundred twenty-one billion, three hundred forty million, one hundred fifteen thousand, three hundred forty-one".