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121342222243007 is a prime number
BaseRepresentation
bin11011100101110000110000…
…000011011001010010111111
3120220122012111002201122222122
4123211300300003121102333
5111401032332343234012
61110023503005433155
734362454246046123
oct3345606003312277
9526565432648878
10121342222243007
1135732a47086507
1211738b2886b7bb
1352926a3ac534c
1421d6dcddb3583
15e065ca1c4e72
hex6e5c300d94bf

121342222243007 has 2 divisors, whose sum is σ = 121342222243008. Its totient is φ = 121342222243006.

The previous prime is 121342222243003. The next prime is 121342222243009. The reversal of 121342222243007 is 700342222243121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121342222243007 - 22 = 121342222243003 is a prime.

Together with 121342222243009, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121342222243001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60671111121503 + 60671111121504.

It is an arithmetic number, because the mean of its divisors is an integer number (60671111121504).

Almost surely, 2121342222243007 is an apocalyptic number.

121342222243007 is a deficient number, since it is larger than the sum of its proper divisors (1).

121342222243007 is an equidigital number, since it uses as much as digits as its factorization.

121342222243007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 35.

Adding to 121342222243007 its reverse (700342222243121), we get a palindrome (821684444486128).

The spelling of 121342222243007 in words is "one hundred twenty-one trillion, three hundred forty-two billion, two hundred twenty-two million, two hundred forty-three thousand, seven".