Base | Representation |
---|---|
bin | 11011100101110000110000… |
… | …000011011001010010111111 |
3 | 120220122012111002201122222122 |
4 | 123211300300003121102333 |
5 | 111401032332343234012 |
6 | 1110023503005433155 |
7 | 34362454246046123 |
oct | 3345606003312277 |
9 | 526565432648878 |
10 | 121342222243007 |
11 | 35732a47086507 |
12 | 11738b2886b7bb |
13 | 52926a3ac534c |
14 | 21d6dcddb3583 |
15 | e065ca1c4e72 |
hex | 6e5c300d94bf |
121342222243007 has 2 divisors, whose sum is σ = 121342222243008. Its totient is φ = 121342222243006.
The previous prime is 121342222243003. The next prime is 121342222243009. The reversal of 121342222243007 is 700342222243121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121342222243007 - 22 = 121342222243003 is a prime.
Together with 121342222243009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121342222243001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60671111121503 + 60671111121504.
It is an arithmetic number, because the mean of its divisors is an integer number (60671111121504).
Almost surely, 2121342222243007 is an apocalyptic number.
121342222243007 is a deficient number, since it is larger than the sum of its proper divisors (1).
121342222243007 is an equidigital number, since it uses as much as digits as its factorization.
121342222243007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 121342222243007 its reverse (700342222243121), we get a palindrome (821684444486128).
The spelling of 121342222243007 in words is "one hundred twenty-one trillion, three hundred forty-two billion, two hundred twenty-two million, two hundred forty-three thousand, seven".
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