Base | Representation |
---|---|
bin | 10001101010000110101… |
… | …110000111011011001101 |
3 | 11022000002210100100011112 |
4 | 101222012232013123031 |
5 | 124340111344412303 |
6 | 2325240324101405 |
7 | 153445125301124 |
oct | 21520656073315 |
9 | 4260083310145 |
10 | 1213441013453 |
11 | 4286878aa479 |
12 | 17720ab34865 |
13 | 8a57215abc6 |
14 | 42a33692abb |
15 | 2186ec030d8 |
hex | 11a86b876cd |
1213441013453 has 2 divisors, whose sum is σ = 1213441013454. Its totient is φ = 1213441013452.
The previous prime is 1213441013419. The next prime is 1213441013461. The reversal of 1213441013453 is 3543101443121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 918910125604 + 294530887849 = 958598^2 + 542707^2 .
It is an emirp because it is prime and its reverse (3543101443121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213441013453 - 224 = 1213424236237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1213441013483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606720506726 + 606720506727.
It is an arithmetic number, because the mean of its divisors is an integer number (606720506727).
Almost surely, 21213441013453 is an apocalyptic number.
It is an amenable number.
1213441013453 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213441013453 is an equidigital number, since it uses as much as digits as its factorization.
1213441013453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1213441013453 its reverse (3543101443121), we get a palindrome (4756542456574).
The spelling of 1213441013453 in words is "one trillion, two hundred thirteen billion, four hundred forty-one million, thirteen thousand, four hundred fifty-three".
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