Base | Representation |
---|---|
bin | 10001101010000111010… |
… | …001001100111110010011 |
3 | 11022000010102122122010112 |
4 | 101222013101030332103 |
5 | 124340121223224334 |
6 | 2325241253151535 |
7 | 153445266416561 |
oct | 21520721147623 |
9 | 4260112578115 |
10 | 1213450211219 |
11 | 428692011934 |
12 | 17721202b5ab |
13 | 8a57402b57c |
14 | 42a349a8a31 |
15 | 2187091d4ce |
hex | 11a8744cf93 |
1213450211219 has 2 divisors, whose sum is σ = 1213450211220. Its totient is φ = 1213450211218.
The previous prime is 1213450211189. The next prime is 1213450211221. The reversal of 1213450211219 is 9121120543121.
It is a strong prime.
It is an emirp because it is prime and its reverse (9121120543121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1213450211219 is a prime.
It is a super-2 number, since 2×12134502112192 (a number of 25 digits) contains 22 as substring.
Together with 1213450211221, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1213450211119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606725105609 + 606725105610.
It is an arithmetic number, because the mean of its divisors is an integer number (606725105610).
Almost surely, 21213450211219 is an apocalyptic number.
1213450211219 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213450211219 is an equidigital number, since it uses as much as digits as its factorization.
1213450211219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 1213450211219 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred eleven thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •