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1213450211219 is a prime number
BaseRepresentation
bin10001101010000111010…
…001001100111110010011
311022000010102122122010112
4101222013101030332103
5124340121223224334
62325241253151535
7153445266416561
oct21520721147623
94260112578115
101213450211219
11428692011934
1217721202b5ab
138a57402b57c
1442a349a8a31
152187091d4ce
hex11a8744cf93

1213450211219 has 2 divisors, whose sum is σ = 1213450211220. Its totient is φ = 1213450211218.

The previous prime is 1213450211189. The next prime is 1213450211221. The reversal of 1213450211219 is 9121120543121.

It is a strong prime.

It is an emirp because it is prime and its reverse (9121120543121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213450211219 is a prime.

It is a super-2 number, since 2×12134502112192 (a number of 25 digits) contains 22 as substring.

Together with 1213450211221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1213450211119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606725105609 + 606725105610.

It is an arithmetic number, because the mean of its divisors is an integer number (606725105610).

Almost surely, 21213450211219 is an apocalyptic number.

1213450211219 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213450211219 is an equidigital number, since it uses as much as digits as its factorization.

1213450211219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 32.

The spelling of 1213450211219 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred eleven thousand, two hundred nineteen".