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1213450445237 is a prime number
BaseRepresentation
bin10001101010000111010…
…010000110000110110101
311022000010110002112010212
4101222013102012012311
5124340121303221422
62325241302155205
7153445301413052
oct21520722060665
94260113075125
101213450445237
11428692161738
12177212122b05
138a5740b0c44
1442a34a2a029
15218709679e2
hex11a874861b5

1213450445237 has 2 divisors, whose sum is σ = 1213450445238. Its totient is φ = 1213450445236.

The previous prime is 1213450445209. The next prime is 1213450445239. The reversal of 1213450445237 is 7325440543121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1159065406801 + 54385038436 = 1076599^2 + 233206^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213450445237 - 236 = 1144730968501 is a prime.

Together with 1213450445239, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213450445194 and 1213450445203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213450445239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606725222618 + 606725222619.

It is an arithmetic number, because the mean of its divisors is an integer number (606725222619).

Almost surely, 21213450445237 is an apocalyptic number.

It is an amenable number.

1213450445237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213450445237 is an equidigital number, since it uses as much as digits as its factorization.

1213450445237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 1213450445237 its reverse (7325440543121), we get a palindrome (8538890988358).

The spelling of 1213450445237 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, four hundred forty-five thousand, two hundred thirty-seven".