12140404411451 has 2 divisors, whose sum is σ = 12140404411452. Its totient is φ = 12140404411450.

The previous prime is 12140404411423. The next prime is 12140404411483. The reversal of 12140404411451 is 15411440404121.

It is an a-pointer prime, because the next prime (12140404411483) can be obtained adding 12140404411451 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12140404411451 is a prime.

It is not a weakly prime, because it can be changed into another prime (12140404011451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070202205725 + 6070202205726.

It is an arithmetic number, because the mean of its divisors is an integer number (6070202205726).

Almost surely, 2^{12140404411451} is an apocalyptic number.

12140404411451 is a deficient number, since it is larger than the sum of its proper divisors (1).

12140404411451 is an equidigital number, since it uses as much as digits as its factorization.

12140404411451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10240, while the sum is 32.

Adding to 12140404411451 its reverse (15411440404121), we get a palindrome (27551844815572).

The spelling of 12140404411451 in words is "twelve trillion, one hundred forty billion, four hundred four million, four hundred eleven thousand, four hundred fifty-one".