1214054431 has 2 divisors, whose sum is σ = 1214054432. Its totient is φ = 1214054430.

The previous prime is 1214054393. The next prime is 1214054437. The reversal of 1214054431 is 1344504121.

It is a strong prime.

It is an emirp because it is prime and its reverse (1344504121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1214054431 - 2¹¹ = 1214052383 is a prime.

It is a super-2 number, since 2×1214054431² = 2947856322861467522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214054396 and 1214054405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214054437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607027215 + 607027216.

It is an arithmetic number, because the mean of its divisors is an integer number (607027216).

Almost surely, 2^1214054431 is an apocalyptic number.

1214054431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214054431 is an equidigital number, since it uses as much as digits as its factorization.

1214054431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

The square root of 1214054431 is about 34843.2838722185. The cubic root of 1214054431 is about 1066.7911056753.

Adding to 1214054431 its reverse (1344504121), we get a palindrome (2558558552).

The spelling of 1214054431 in words is "one billion, two hundred fourteen million, fifty-four thousand, four hundred thirty-one".