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12141140132453 is a prime number
BaseRepresentation
bin1011000010101101010001…
…0110000100001001100101
31120222200101221010201020112
42300223110112010021211
53042410023333214303
641453321320542405
72362111525234103
oct260532426041145
946880357121215
1012141140132453
1139610350a4372
12144104b321a05
136a0b9b544467
142dd8c47d4c73
15160c43ca40d8
hexb0ad4584265

12141140132453 has 2 divisors, whose sum is σ = 12141140132454. Its totient is φ = 12141140132452.

The previous prime is 12141140132399. The next prime is 12141140132461. The reversal of 12141140132453 is 35423104114121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9879599371489 + 2261540760964 = 3143183^2 + 1503842^2 .

It is a cyclic number.

It is not a de Polignac number, because 12141140132453 - 28 = 12141140132197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12141140132053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070570066226 + 6070570066227.

It is an arithmetic number, because the mean of its divisors is an integer number (6070570066227).

Almost surely, 212141140132453 is an apocalyptic number.

It is an amenable number.

12141140132453 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141140132453 is an equidigital number, since it uses as much as digits as its factorization.

12141140132453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 12141140132453 its reverse (35423104114121), we get a palindrome (47564244246574).

The spelling of 12141140132453 in words is "twelve trillion, one hundred forty-one billion, one hundred forty million, one hundred thirty-two thousand, four hundred fifty-three".