Base | Representation |
---|---|
bin | 10110100111100100… |
… | …10001000110100111 |
3 | 1011100021101121201021 |
4 | 23103302101012213 |
5 | 144332113320143 |
6 | 5324540512011 |
7 | 606626453542 |
oct | 132362210647 |
9 | 34307347637 |
10 | 12143104423 |
11 | 517151409a |
12 | 242a84b607 |
13 | 11b69babb8 |
14 | 832a2d859 |
15 | 4b10dbced |
hex | 2d3c911a7 |
12143104423 has 2 divisors, whose sum is σ = 12143104424. Its totient is φ = 12143104422.
The previous prime is 12143104361. The next prime is 12143104427. The reversal of 12143104423 is 32440134121.
12143104423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12143104423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12143104427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071552211 + 6071552212.
It is an arithmetic number, because the mean of its divisors is an integer number (6071552212).
Almost surely, 212143104423 is an apocalyptic number.
12143104423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143104423 is an equidigital number, since it uses as much as digits as its factorization.
12143104423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12143104423 its reverse (32440134121), we get a palindrome (44583238544).
The spelling of 12143104423 in words is "twelve billion, one hundred forty-three million, one hundred four thousand, four hundred twenty-three".
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