Base | Representation |
---|---|
bin | 10110100111100110… |
… | …00011111000101111 |
3 | 1011100021210012001021 |
4 | 23103303003320233 |
5 | 144332141444211 |
6 | 5324545155011 |
7 | 606631311145 |
oct | 132363037057 |
9 | 34307705037 |
10 | 12143312431 |
11 | 51716463a8 |
12 | 242a92ba67 |
13 | 11b6a61793 |
14 | 832a85595 |
15 | 4b112d771 |
hex | 2d3cc3e2f |
12143312431 has 2 divisors, whose sum is σ = 12143312432. Its totient is φ = 12143312430.
The previous prime is 12143312417. The next prime is 12143312437. The reversal of 12143312431 is 13421334121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12143312431 - 29 = 12143311919 is a prime.
It is a super-2 number, since 2×121433124312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12143312396 and 12143312405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12143312437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071656215 + 6071656216.
It is an arithmetic number, because the mean of its divisors is an integer number (6071656216).
Almost surely, 212143312431 is an apocalyptic number.
12143312431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143312431 is an equidigital number, since it uses as much as digits as its factorization.
12143312431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 25.
Adding to 12143312431 its reverse (13421334121), we get a palindrome (25564646552).
The spelling of 12143312431 in words is "twelve billion, one hundred forty-three million, three hundred twelve thousand, four hundred thirty-one".
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