Base | Representation |
---|---|
bin | 111000100011000011… |
… | …0100101001001011111 |
3 | 102121110000210001120111 |
4 | 1301012012211021133 |
5 | 3442144403330211 |
6 | 131441522030451 |
7 | 11526164202016 |
oct | 1610606451137 |
9 | 377400701514 |
10 | 121435214431 |
11 | 47556015a53 |
12 | 1b6504a8427 |
13 | b5b364538b |
14 | 5c3dbc3a7d |
15 | 325aea4421 |
hex | 1c461a525f |
121435214431 has 2 divisors, whose sum is σ = 121435214432. Its totient is φ = 121435214430.
The previous prime is 121435214399. The next prime is 121435214437. The reversal of 121435214431 is 134412534121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121435214431 - 25 = 121435214399 is a prime.
It is a super-2 number, since 2×1214352144312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121435214393 and 121435214402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121435214437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60717607215 + 60717607216.
It is an arithmetic number, because the mean of its divisors is an integer number (60717607216).
Almost surely, 2121435214431 is an apocalyptic number.
121435214431 is a deficient number, since it is larger than the sum of its proper divisors (1).
121435214431 is an equidigital number, since it uses as much as digits as its factorization.
121435214431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 121435214431 its reverse (134412534121), we get a palindrome (255847748552).
The spelling of 121435214431 in words is "one hundred twenty-one billion, four hundred thirty-five million, two hundred fourteen thousand, four hundred thirty-one".
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