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121435214471 is a prime number
BaseRepresentation
bin111000100011000011…
…0100101001010000111
3102121110000210001121222
41301012012211022013
53442144403330341
6131441522030555
711526164202104
oct1610606451207
9377400701558
10121435214471
1147556015a8a
121b6504a845b
13b5b36453bc
145c3dbc3aab
15325aea444b
hex1c461a5287

121435214471 has 2 divisors, whose sum is σ = 121435214472. Its totient is φ = 121435214470.

The previous prime is 121435214441. The next prime is 121435214477. The reversal of 121435214471 is 174412534121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121435214471 - 234 = 104255345287 is a prime.

It is a super-3 number, since 3×1214352144713 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121435214477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60717607235 + 60717607236.

It is an arithmetic number, because the mean of its divisors is an integer number (60717607236).

Almost surely, 2121435214471 is an apocalyptic number.

121435214471 is a deficient number, since it is larger than the sum of its proper divisors (1).

121435214471 is an equidigital number, since it uses as much as digits as its factorization.

121435214471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 26880, while the sum is 35.

Adding to 121435214471 its reverse (174412534121), we get a palindrome (295847748592).

The spelling of 121435214471 in words is "one hundred twenty-one billion, four hundred thirty-five million, two hundred fourteen thousand, four hundred seventy-one".