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121435214441 is a prime number
BaseRepresentation
bin111000100011000011…
…0100101001001101001
3102121110000210001120212
41301012012211021221
53442144403330231
6131441522030505
711526164202032
oct1610606451151
9377400701525
10121435214441
1147556015a62
121b6504a8435
13b5b3645398
145c3dbc3a89
15325aea442b
hex1c461a5269

121435214441 has 2 divisors, whose sum is σ = 121435214442. Its totient is φ = 121435214440.

The previous prime is 121435214437. The next prime is 121435214471. The reversal of 121435214441 is 144412534121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107302760041 + 14132454400 = 327571^2 + 118880^2 .

It is a cyclic number.

It is not a de Polignac number, because 121435214441 - 22 = 121435214437 is a prime.

It is a super-2 number, since 2×1214352144412 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121435214398 and 121435214407.

It is not a weakly prime, because it can be changed into another prime (121435214431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60717607220 + 60717607221.

It is an arithmetic number, because the mean of its divisors is an integer number (60717607221).

Almost surely, 2121435214441 is an apocalyptic number.

It is an amenable number.

121435214441 is a deficient number, since it is larger than the sum of its proper divisors (1).

121435214441 is an equidigital number, since it uses as much as digits as its factorization.

121435214441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15360, while the sum is 32.

Adding to 121435214441 its reverse (144412534121), we get a palindrome (265847748562).

The spelling of 121435214441 in words is "one hundred twenty-one billion, four hundred thirty-five million, two hundred fourteen thousand, four hundred forty-one".