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12143531437 is a prime number
BaseRepresentation
bin10110100111100111…
…11001010110101101
31011100022012022110121
423103303321112231
5144332221001222
65324554004541
7606633212512
oct132363712655
934308168417
1012143531437
1151717859a4
12242aa16751
1311b6b0a37b
14832b01309
154b11735c7
hex2d3cf95ad

12143531437 has 2 divisors, whose sum is σ = 12143531438. Its totient is φ = 12143531436.

The previous prime is 12143531399. The next prime is 12143531447. The reversal of 12143531437 is 73413534121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11254239396 + 889292041 = 106086^2 + 29821^2 .

It is an emirp because it is prime and its reverse (73413534121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12143531437 is a prime.

It is a super-2 number, since 2×121435314372 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143531447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071765718 + 6071765719.

It is an arithmetic number, because the mean of its divisors is an integer number (6071765719).

Almost surely, 212143531437 is an apocalyptic number.

It is an amenable number.

12143531437 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143531437 is an equidigital number, since it uses as much as digits as its factorization.

12143531437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30240, while the sum is 34.

The spelling of 12143531437 in words is "twelve billion, one hundred forty-three million, five hundred thirty-one thousand, four hundred thirty-seven".