Base | Representation |
---|---|
bin | 10001101011001000111… |
… | …000110011001100111111 |
3 | 11022002222011012002222121 |
4 | 101223020320303030333 |
5 | 124344400041013323 |
6 | 2325542421223411 |
7 | 153514465046425 |
oct | 21531070631477 |
9 | 4262864162877 |
10 | 1214551110463 |
11 | 4290a7490819 |
12 | 17747a861b67 |
13 | 8a6bb135642 |
14 | 42adac9d115 |
15 | 218d73d0a5d |
hex | 11ac8e3333f |
1214551110463 has 2 divisors, whose sum is σ = 1214551110464. Its totient is φ = 1214551110462.
The previous prime is 1214551110433. The next prime is 1214551110467. The reversal of 1214551110463 is 3640111554121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1214551110463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1214551110467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607275555231 + 607275555232.
It is an arithmetic number, because the mean of its divisors is an integer number (607275555232).
Almost surely, 21214551110463 is an apocalyptic number.
1214551110463 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214551110463 is an equidigital number, since it uses as much as digits as its factorization.
1214551110463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 1214551110463 its reverse (3640111554121), we get a palindrome (4854662664584).
The spelling of 1214551110463 in words is "one trillion, two hundred fourteen billion, five hundred fifty-one million, one hundred ten thousand, four hundred sixty-three".
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