Base | Representation |
---|---|
bin | 10110101000110000… |
… | …01000010111110111 |
3 | 1011100222001220020020 |
4 | 23110120020113313 |
5 | 144342133431020 |
6 | 5325533340223 |
7 | 610110023511 |
oct | 132430102767 |
9 | 34328056206 |
10 | 12153030135 |
11 | 5177083464 |
12 | 2432037673 |
13 | 11b8a849bc |
14 | 834094bb1 |
15 | 4b1decc40 |
hex | 2d46085f7 |
12153030135 has 64 divisors (see below), whose sum is σ = 20656512000. Its totient is φ = 6084329472.
The previous prime is 12153030133. The next prime is 12153030137. The reversal of 12153030135 is 53103035121.
12153030135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (12153030133) and next prime (12153030137).
It is not a de Polignac number, because 12153030135 - 21 = 12153030133 is a prime.
It is a super-2 number, since 2×121530301352 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12153030133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20288566 + ... + 20289164.
It is an arithmetic number, because the mean of its divisors is an integer number (322758000).
Almost surely, 212153030135 is an apocalyptic number.
12153030135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12153030135 is a deficient number, since it is larger than the sum of its proper divisors (8503481865).
12153030135 is a wasteful number, since it uses less digits than its factorization.
12153030135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1160.
The product of its (nonzero) digits is 1350, while the sum is 24.
Adding to 12153030135 its reverse (53103035121), we get a palindrome (65256065256).
The spelling of 12153030135 in words is "twelve billion, one hundred fifty-three million, thirty thousand, one hundred thirty-five".
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