Base | Representation |
---|---|
bin | 111000100101111010… |
… | …1101101101001011101 |
3 | 102121200201212122022111 |
4 | 1301023311231221131 |
5 | 3442344023043333 |
6 | 131455240514021 |
7 | 11531443221655 |
oct | 1611365555135 |
9 | 377621778274 |
10 | 121531456093 |
11 | 475a537a813 |
12 | 1b67877b911 |
13 | b5ca5712c8 |
14 | 5c4c8b7365 |
15 | 32646654cd |
hex | 1c4bd6da5d |
121531456093 has 2 divisors, whose sum is σ = 121531456094. Its totient is φ = 121531456092.
The previous prime is 121531456061. The next prime is 121531456103. The reversal of 121531456093 is 390654135121.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110827070649 + 10704385444 = 332907^2 + 103462^2 .
It is a cyclic number.
It is not a de Polignac number, because 121531456093 - 25 = 121531456061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121531456693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60765728046 + 60765728047.
It is an arithmetic number, because the mean of its divisors is an integer number (60765728047).
Almost surely, 2121531456093 is an apocalyptic number.
It is an amenable number.
121531456093 is a deficient number, since it is larger than the sum of its proper divisors (1).
121531456093 is an equidigital number, since it uses as much as digits as its factorization.
121531456093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 121531456093 in words is "one hundred twenty-one billion, five hundred thirty-one million, four hundred fifty-six thousand, ninety-three".
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