Base | Representation |
---|---|
bin | 111000100101111100… |
… | …1110010011001100101 |
3 | 102121200210212220101112 |
4 | 1301023321302121211 |
5 | 3442344311233013 |
6 | 131455315434405 |
7 | 11531455260536 |
oct | 1611371623145 |
9 | 377623786345 |
10 | 121532524133 |
11 | 475a5a3a199 |
12 | 1b678bb5a05 |
13 | b5ca856497 |
14 | 5c4cab468d |
15 | 32647c6ba8 |
hex | 1c4be72665 |
121532524133 has 2 divisors, whose sum is σ = 121532524134. Its totient is φ = 121532524132.
The previous prime is 121532524109. The next prime is 121532524151. The reversal of 121532524133 is 331425235121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111487874404 + 10044649729 = 333898^2 + 100223^2 .
It is a cyclic number.
It is not a de Polignac number, because 121532524133 - 220 = 121531475557 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121532524133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121532524033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60766262066 + 60766262067.
It is an arithmetic number, because the mean of its divisors is an integer number (60766262067).
Almost surely, 2121532524133 is an apocalyptic number.
It is an amenable number.
121532524133 is a deficient number, since it is larger than the sum of its proper divisors (1).
121532524133 is an equidigital number, since it uses as much as digits as its factorization.
121532524133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21600, while the sum is 32.
Adding to 121532524133 its reverse (331425235121), we get a palindrome (452957759254).
The spelling of 121532524133 in words is "one hundred twenty-one billion, five hundred thirty-two million, five hundred twenty-four thousand, one hundred thirty-three".
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