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1215414313031 is a prime number
BaseRepresentation
bin10001101011111100010…
…101101010000001000111
311022012012022110100022002
4101223330111222001013
5124403132031004111
62330204214455515
7153545046126122
oct21537425520107
94265168410262
101215414313031
114294aa76a676
1217767b96459b
138a7c7c170a9
1442b7d79b3b9
152193808e63b
hex11afc56a047

1215414313031 has 2 divisors, whose sum is σ = 1215414313032. Its totient is φ = 1215414313030.

The previous prime is 1215414312971. The next prime is 1215414313073. The reversal of 1215414313031 is 1303134145121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1215414313031 is a prime.

It is a super-2 number, since 2×12154143130312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1215414312985 and 1215414313003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1215414313831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607707156515 + 607707156516.

It is an arithmetic number, because the mean of its divisors is an integer number (607707156516).

Almost surely, 21215414313031 is an apocalyptic number.

1215414313031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1215414313031 is an equidigital number, since it uses as much as digits as its factorization.

1215414313031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1215414313031 its reverse (1303134145121), we get a palindrome (2518548458152).

The spelling of 1215414313031 in words is "one trillion, two hundred fifteen billion, four hundred fourteen million, three hundred thirteen thousand, thirty-one".