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121573265217113 is a prime number
BaseRepresentation
bin11011101001000111111011…
…010010011001011001011001
3120221110021211212211211100202
4123221013323102121121121
5111413324021343421423
61110321553110311545
734415243562655613
oct3351077322313131
9527407755754322
10121573265217113
1135811a28896606
12117758686585b5
1352ab4045b1c48
14220426ac35db3
15e0c5edae2728
hex6e91fb499659

121573265217113 has 2 divisors, whose sum is σ = 121573265217114. Its totient is φ = 121573265217112.

The previous prime is 121573265217067. The next prime is 121573265217137. The reversal of 121573265217113 is 311712562375121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113694706723984 + 7878558493129 = 10662772^2 + 2806877^2 .

It is an emirp because it is prime and its reverse (311712562375121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121573265217113 - 224 = 121573248439897 is a prime.

It is not a weakly prime, because it can be changed into another prime (121573265217163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60786632608556 + 60786632608557.

It is an arithmetic number, because the mean of its divisors is an integer number (60786632608557).

Almost surely, 2121573265217113 is an apocalyptic number.

It is an amenable number.

121573265217113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121573265217113 is an equidigital number, since it uses as much as digits as its factorization.

121573265217113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 529200, while the sum is 47.

The spelling of 121573265217113 in words is "one hundred twenty-one trillion, five hundred seventy-three billion, two hundred sixty-five million, two hundred seventeen thousand, one hundred thirteen".