Base | Representation |
---|---|
bin | 111000101001000001… |
… | …0000000011010011111 |
3 | 102121221222100120222001 |
4 | 1301102002000122133 |
5 | 3443102121420413 |
6 | 131513431303131 |
7 | 11534144230201 |
oct | 1612202003237 |
9 | 377858316861 |
10 | 121635341983 |
11 | 47648a85821 |
12 | 1b6a751aaa7 |
13 | b615c4574c |
14 | 5c5c5da771 |
15 | 326d8364dd |
hex | 1c5208069f |
121635341983 has 2 divisors, whose sum is σ = 121635341984. Its totient is φ = 121635341982.
The previous prime is 121635341959. The next prime is 121635342029. The reversal of 121635341983 is 389143536121.
It is an a-pointer prime, because the next prime (121635342029) can be obtained adding 121635341983 to its sum of digits (46).
It is a weak prime.
It is an emirp because it is prime and its reverse (389143536121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121635341983 - 213 = 121635333791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121635341923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60817670991 + 60817670992.
It is an arithmetic number, because the mean of its divisors is an integer number (60817670992).
Almost surely, 2121635341983 is an apocalyptic number.
121635341983 is a deficient number, since it is larger than the sum of its proper divisors (1).
121635341983 is an equidigital number, since it uses as much as digits as its factorization.
121635341983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 466560, while the sum is 46.
The spelling of 121635341983 in words is "one hundred twenty-one billion, six hundred thirty-five million, three hundred forty-one thousand, nine hundred eighty-three".
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