12165143335067 has 2 divisors, whose sum is σ = 12165143335068. Its totient is φ = 12165143335066.

The previous prime is 12165143335063. The next prime is 12165143335069. The reversal of 12165143335067 is 76053334156121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12165143335067 - 2² = 12165143335063 is a prime.

Together with 12165143335069, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12165143335063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6082571667533 + 6082571667534.

It is an arithmetic number, because the mean of its divisors is an integer number (6082571667534).

Almost surely, 2^{12165143335067} is an apocalyptic number.

12165143335067 is a deficient number, since it is larger than the sum of its proper divisors (1).

12165143335067 is an equidigital number, since it uses as much as digits as its factorization.

12165143335067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 47.

The spelling of 12165143335067 in words is "twelve trillion, one hundred sixty-five billion, one hundred forty-three million, three hundred thirty-five thousand, sixty-seven".