12200000999981 has 2 divisors, whose sum is σ = 12200000999982. Its totient is φ = 12200000999980.

The previous prime is 12200000999951. The next prime is 12200000999983. The reversal of 12200000999981 is 18999900000221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11998319171881 + 201681828100 = 3463859^2 + 449090^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12200000999981 is a prime.

It is a super-2 number, since 2×12200000999981² (a number of 27 digits) contains 22 as substring.

Together with 12200000999983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12200000999983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100000499990 + 6100000499991.

It is an arithmetic number, because the mean of its divisors is an integer number (6100000499991).

Almost surely, 2^{12200000999981} is an apocalyptic number.

It is an amenable number.

12200000999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

12200000999981 is an equidigital number, since it uses as much as digits as its factorization.

12200000999981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 50.

The spelling of 12200000999981 in words is "twelve trillion, two hundred billion, nine hundred ninety-nine thousand, nine hundred eighty-one".