Base | Representation |
---|---|
bin | 1011000110001000111101… |
… | …0010011101000001011111 |
3 | 1121012022121201102020211122 |
4 | 2301202033102131001133 |
5 | 3044341311420144444 |
6 | 41540353105241155 |
7 | 2366300061212144 |
oct | 261421722350137 |
9 | 47168551366748 |
10 | 12200111099999 |
11 | 3984046729089 |
12 | 14505686331bb |
13 | 6a6608a3a9b4 |
14 | 3026ba7403cb |
15 | 162545edd4ee |
hex | b188f49d05f |
12200111099999 has 2 divisors, whose sum is σ = 12200111100000. Its totient is φ = 12200111099998.
The previous prime is 12200111099959. The next prime is 12200111100011. The reversal of 12200111099999 is 99999011100221.
12200111099999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (99999011100221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12200111099999 - 240 = 11100599472223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12200111099999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200111099959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100055549999 + 6100055550000.
It is an arithmetic number, because the mean of its divisors is an integer number (6100055550000).
Almost surely, 212200111099999 is an apocalyptic number.
12200111099999 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200111099999 is an equidigital number, since it uses as much as digits as its factorization.
12200111099999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 236196, while the sum is 53.
The spelling of 12200111099999 in words is "twelve trillion, two hundred billion, one hundred eleven million, ninety-nine thousand, nine hundred ninety-nine".
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