12200431431231 has 24 divisors (see below), whose sum is σ = 18416353063680. Its totient is φ = 7775435754576.

The previous prime is 12200431431217. The next prime is 12200431431233. The reversal of 12200431431231 is 13213413400221.

12200431431231 is a `hidden beast` number, since 1 + 2 + 2 + 0 + 0 + 4 + 314 + 312 + 31 = 666.

12200431431231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12200431431231 - 2¹⁷ = 12200431300159 is a prime.

It is a super-2 number, since 2×12200431431231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12200431431195 and 12200431431204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12200431431233) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 335361201 + ... + 335397578.

It is an arithmetic number, because the mean of its divisors is an integer number (767348044320).

Almost surely, 2^{12200431431231} is an apocalyptic number.

12200431431231 is a deficient number, since it is larger than the sum of its proper divisors (6215921632449).

12200431431231 is a wasteful number, since it uses less digits than its factorization.

12200431431231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670758875 (or 670758872 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 12200431431231 its reverse (13213413400221), we get a palindrome (25413844831452).

The spelling of 12200431431231 in words is "twelve trillion, two hundred billion, four hundred thirty-one million, four hundred thirty-one thousand, two hundred thirty-one".