Base | Representation |
---|---|
bin | 1011000110001010110111… |
… | …0011111110100101011111 |
3 | 1121012100221102000212102112 |
4 | 2301202231303332211133 |
5 | 3044343334020022303 |
6 | 41540520001344235 |
7 | 2366315550062603 |
oct | 261425563764537 |
9 | 47170842025375 |
10 | 12200623204703 |
11 | 3984289802a0a |
12 | 145069003807b |
13 | 6a668ab7062b |
14 | 302728767503 |
15 | 162575e480d8 |
hex | b18adcfe95f |
12200623204703 has 2 divisors, whose sum is σ = 12200623204704. Its totient is φ = 12200623204702.
The previous prime is 12200623204621. The next prime is 12200623204723. The reversal of 12200623204703 is 30740232600221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12200623204703 - 222 = 12200619010399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12200623204703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200623204723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100311602351 + 6100311602352.
It is an arithmetic number, because the mean of its divisors is an integer number (6100311602352).
Almost surely, 212200623204703 is an apocalyptic number.
12200623204703 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200623204703 is an equidigital number, since it uses as much as digits as its factorization.
12200623204703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 12200623204703 its reverse (30740232600221), we get a palindrome (42940855804924).
The spelling of 12200623204703 in words is "twelve trillion, two hundred billion, six hundred twenty-three million, two hundred four thousand, seven hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •