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122010012543413 is a prime number
BaseRepresentation
bin11011101111011110101011…
…011101001110100110110101
3121000000001011112222210100202
4123233132223131032212311
5111443003001202342123
61111254343113250245
734461634564666001
oct3357365335164665
9530001145883322
10122010012543413
1135970179317065
1211826436403985
135310658150937
14221b45d5c9701
15e18b6166ca28
hex6ef7ab74e9b5

122010012543413 has 2 divisors, whose sum is σ = 122010012543414. Its totient is φ = 122010012543412.

The previous prime is 122010012543379. The next prime is 122010012543437. The reversal of 122010012543413 is 314345210010221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111149408878564 + 10860603664849 = 10542742^2 + 3295543^2 .

It is a cyclic number.

It is not a de Polignac number, because 122010012543413 - 216 = 122010012477877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122010012542413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61005006271706 + 61005006271707.

It is an arithmetic number, because the mean of its divisors is an integer number (61005006271707).

Almost surely, 2122010012543413 is an apocalyptic number.

It is an amenable number.

122010012543413 is a deficient number, since it is larger than the sum of its proper divisors (1).

122010012543413 is an equidigital number, since it uses as much as digits as its factorization.

122010012543413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 122010012543413 its reverse (314345210010221), we get a palindrome (436355222553634).

The spelling of 122010012543413 in words is "one hundred twenty-two trillion, ten billion, twelve million, five hundred forty-three thousand, four hundred thirteen".