Base | Representation |
---|---|
bin | 1011000110001100101011… |
… | …1100101010010000110111 |
3 | 1121012102012110211020222122 |
4 | 2301203022330222100313 |
5 | 3044400334134120043 |
6 | 41541040302350155 |
7 | 2366333633664263 |
oct | 261431274522067 |
9 | 47172173736878 |
10 | 12201112020023 |
11 | 398450a720113 |
12 | 14507a788b35b |
13 | 6a673820a874 |
14 | 30277364b0a3 |
15 | 1625a3d02368 |
hex | b18caf2a437 |
12201112020023 has 2 divisors, whose sum is σ = 12201112020024. Its totient is φ = 12201112020022.
The previous prime is 12201112019977. The next prime is 12201112020043. The reversal of 12201112020023 is 32002021110221.
12201112020023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12201112020023 - 26 = 12201112019959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12201112019983 and 12201112020010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12201112020043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100556010011 + 6100556010012.
It is an arithmetic number, because the mean of its divisors is an integer number (6100556010012).
Almost surely, 212201112020023 is an apocalyptic number.
12201112020023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201112020023 is an equidigital number, since it uses as much as digits as its factorization.
12201112020023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 12201112020023 its reverse (32002021110221), we get a palindrome (44203133130244).
The spelling of 12201112020023 in words is "twelve trillion, two hundred one billion, one hundred twelve million, twenty thousand, twenty-three".
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