Search a number
-
+
1220120200001 is a prime number
BaseRepresentation
bin10001110000010100110…
…101001100001101000001
311022122100021102011122002
4101300110311030031001
5124442301232400001
62332303202153345
7154102500403163
oct21602465141501
94278307364562
101220120200001
114304a505415a
12178573952855
138b097b595b1
14430a877c933
1521b1129b46b
hex11c14d4c341

1220120200001 has 2 divisors, whose sum is σ = 1220120200002. Its totient is φ = 1220120200000.

The previous prime is 1220120199943. The next prime is 1220120200003. The reversal of 1220120200001 is 1000020210221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1154386931776 + 65733268225 = 1074424^2 + 256385^2 .

It is an emirp because it is prime and its reverse (1000020210221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1220120200001 - 218 = 1220119937857 is a prime.

Together with 1220120200003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1220120200003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610060100000 + 610060100001.

It is an arithmetic number, because the mean of its divisors is an integer number (610060100001).

Almost surely, 21220120200001 is an apocalyptic number.

It is an amenable number.

1220120200001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220120200001 is an equidigital number, since it uses as much as digits as its factorization.

1220120200001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 11.

Adding to 1220120200001 its reverse (1000020210221), we get a palindrome (2220140410222).

The spelling of 1220120200001 in words is "one trillion, two hundred twenty billion, one hundred twenty million, two hundred thousand, one".