Base | Representation |
---|---|
bin | 11011101111100000101010… |
… | …010001001110101010010111 |
3 | 121000000020122211101002021201 |
4 | 123233200222101032222113 |
5 | 111443021330331314333 |
6 | 1111255334154253331 |
7 | 34462041400652356 |
oct | 3357405221165227 |
9 | 530006584332251 |
10 | 122012140104343 |
11 | 3597107026a085 |
12 | 1182692aa27247 |
13 | 5310906b6b528 |
14 | 221b5c1dab99d |
15 | e18c3832b17d |
hex | 6ef82a44ea97 |
122012140104343 has 2 divisors, whose sum is σ = 122012140104344. Its totient is φ = 122012140104342.
The previous prime is 122012140104301. The next prime is 122012140104401. The reversal of 122012140104343 is 343401041210221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122012140104343 - 233 = 122003550169751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122012140104143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61006070052171 + 61006070052172.
It is an arithmetic number, because the mean of its divisors is an integer number (61006070052172).
Almost surely, 2122012140104343 is an apocalyptic number.
122012140104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
122012140104343 is an equidigital number, since it uses as much as digits as its factorization.
122012140104343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 122012140104343 its reverse (343401041210221), we get a palindrome (465413181314564).
The spelling of 122012140104343 in words is "one hundred twenty-two trillion, twelve billion, one hundred forty million, one hundred four thousand, three hundred forty-three".
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