Base | Representation |
---|---|
bin | 10001110000011001101… |
… | …010001100001000100011 |
3 | 11022122112220211111202221 |
4 | 101300121222030020203 |
5 | 124442433001432321 |
6 | 2332315214251511 |
7 | 154104503042215 |
oct | 21603152141043 |
9 | 4278486744687 |
10 | 1220201202211 |
11 | 43053684a332 |
12 | 178596ab6b97 |
13 | 8b0ab87abb4 |
14 | 430b54265b5 |
15 | 21b1844be41 |
hex | 11c19a8c223 |
1220201202211 has 2 divisors, whose sum is σ = 1220201202212. Its totient is φ = 1220201202210.
The previous prime is 1220201202197. The next prime is 1220201202239. The reversal of 1220201202211 is 1122021020221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1220201202211 - 233 = 1211611267619 is a prime.
It is a super-2 number, since 2×12202012022112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1220201202611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610100601105 + 610100601106.
It is an arithmetic number, because the mean of its divisors is an integer number (610100601106).
Almost surely, 21220201202211 is an apocalyptic number.
1220201202211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220201202211 is an equidigital number, since it uses as much as digits as its factorization.
1220201202211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1220201202211 its reverse (1122021020221), we get a palindrome (2342222222432).
It can be divided in two parts, 122020 and 1202211, that added together give a palindrome (1324231).
The spelling of 1220201202211 in words is "one trillion, two hundred twenty billion, two hundred one million, two hundred two thousand, two hundred eleven".
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