12203111300999 has 2 divisors, whose sum is σ = 12203111301000. Its totient is φ = 12203111300998.

The previous prime is 12203111300971. The next prime is 12203111301001. The reversal of 12203111300999 is 99900311130221.

12203111300999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12203111300999 - 2²⁰ = 12203110252423 is a prime.

Together with 12203111301001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12203111300099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101555650499 + 6101555650500.

It is an arithmetic number, because the mean of its divisors is an integer number (6101555650500).

Almost surely, 2^{12203111300999} is an apocalyptic number.

12203111300999 is a deficient number, since it is larger than the sum of its proper divisors (1).

12203111300999 is an equidigital number, since it uses as much as digits as its factorization.

12203111300999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 41.

The spelling of 12203111300999 in words is "twelve trillion, two hundred three billion, one hundred eleven million, three hundred thousand, nine hundred ninety-nine".