Base | Representation |
---|---|
bin | 1011000110010101100111… |
… | …1000010010000010110011 |
3 | 1121012122101121001222111020 |
4 | 2301211121320102002303 |
5 | 3044420242030423011 |
6 | 41542114243550523 |
7 | 2366450232414612 |
oct | 261453170220263 |
9 | 47178347058436 |
10 | 12203510014131 |
11 | 3985530292627 |
12 | 145115698b443 |
13 | 6a6a2ac734a7 |
14 | 30291dd07879 |
15 | 1626945ce006 |
hex | b1959e120b3 |
12203510014131 has 32 divisors (see below), whose sum is σ = 17558743222080. Its totient is φ = 7510408249344.
The previous prime is 12203510014127. The next prime is 12203510014159. The reversal of 12203510014131 is 13141001530221.
It is not a de Polignac number, because 12203510014131 - 22 = 12203510014127 is a prime.
It is a super-2 number, since 2×122035100141312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12203510014181) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8494371 + ... + 9826563.
It is an arithmetic number, because the mean of its divisors is an integer number (548710725690).
Almost surely, 212203510014131 is an apocalyptic number.
12203510014131 is a deficient number, since it is larger than the sum of its proper divisors (5355233207949).
12203510014131 is a wasteful number, since it uses less digits than its factorization.
12203510014131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1335655.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 12203510014131 its reverse (13141001530221), we get a palindrome (25344511544352).
The spelling of 12203510014131 in words is "twelve trillion, two hundred three billion, five hundred ten million, fourteen thousand, one hundred thirty-one".
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