Base | Representation |
---|---|
bin | 1011000110101110100101… |
… | …0011010100001110000101 |
3 | 1121020021200121120000020011 |
4 | 2301223221103110032011 |
5 | 3100023003032210432 |
6 | 41545143225510221 |
7 | 2400105262555264 |
oct | 261535123241605 |
9 | 47207617500204 |
10 | 12210211210117 |
11 | 39883599aa328 |
12 | 1452507042371 |
13 | 6a75583a9b0b |
14 | 302d97cc25db |
15 | 162937a73847 |
hex | b1ae94d4385 |
12210211210117 has 2 divisors, whose sum is σ = 12210211210118. Its totient is φ = 12210211210116.
The previous prime is 12210211209971. The next prime is 12210211210121. The reversal of 12210211210117 is 71101211201221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9493799602401 + 2716411607716 = 3081201^2 + 1648154^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12210211210117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12210211210157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105105605058 + 6105105605059.
It is an arithmetic number, because the mean of its divisors is an integer number (6105105605059).
Almost surely, 212210211210117 is an apocalyptic number.
It is an amenable number.
12210211210117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210211210117 is an equidigital number, since it uses as much as digits as its factorization.
12210211210117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 12210211210117 its reverse (71101211201221), we get a palindrome (83311422411338).
The spelling of 12210211210117 in words is "twelve trillion, two hundred ten billion, two hundred eleven million, two hundred ten thousand, one hundred seventeen".
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