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122111011111 is a prime number
BaseRepresentation
bin111000110111001100…
…0100010100100100111
3102200012010102002100011
41301232120202210213
54000040404323421
6132032542431051
711552011316515
oct1615630424447
9380163362304
10122111011111
1147872534001
121b7ba892487
13b69065c07b
145ca585b4b5
15329a4954e1
hex1c6e622927

122111011111 has 2 divisors, whose sum is σ = 122111011112. Its totient is φ = 122111011110.

The previous prime is 122111011019. The next prime is 122111011147. The reversal of 122111011111 is 111110111221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122111011111 - 213 = 122111002919 is a prime.

It is a super-5 number, since 5×1221110111115 (a number of 57 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 122111011091 and 122111011100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122111011171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61055505555 + 61055505556.

It is an arithmetic number, because the mean of its divisors is an integer number (61055505556).

Almost surely, 2122111011111 is an apocalyptic number.

122111011111 is a deficient number, since it is larger than the sum of its proper divisors (1).

122111011111 is an equidigital number, since it uses as much as digits as its factorization.

122111011111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 122111011111 its reverse (111110111221), we get a palindrome (233221122332).

The spelling of 122111011111 in words is "one hundred twenty-two billion, one hundred eleven million, eleven thousand, one hundred eleven".