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122111011147 is a prime number
BaseRepresentation
bin111000110111001100…
…0100010100101001011
3102200012010102002101111
41301232120202211023
54000040404324042
6132032542431151
711552011316566
oct1615630424513
9380163362344
10122111011147
1147872534034
121b7ba8924b7
13b69065c0a8
145ca585b4dd
15329a495517
hex1c6e62294b

122111011147 has 2 divisors, whose sum is σ = 122111011148. Its totient is φ = 122111011146.

The previous prime is 122111011111. The next prime is 122111011157. The reversal of 122111011147 is 741110111221.

It is a strong prime.

It is an emirp because it is prime and its reverse (741110111221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122111011147 - 27 = 122111011019 is a prime.

It is a super-2 number, since 2×1221110111472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122111011157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61055505573 + 61055505574.

It is an arithmetic number, because the mean of its divisors is an integer number (61055505574).

Almost surely, 2122111011147 is an apocalyptic number.

122111011147 is a deficient number, since it is larger than the sum of its proper divisors (1).

122111011147 is an equidigital number, since it uses as much as digits as its factorization.

122111011147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 22.

Adding to 122111011147 its reverse (741110111221), we get a palindrome (863221122368).

The spelling of 122111011147 in words is "one hundred twenty-two billion, one hundred eleven million, eleven thousand, one hundred forty-seven".