Base | Representation |
---|---|
bin | 1011000110110010010001… |
… | …0000000001000100101111 |
3 | 1121020101020112111221200101 |
4 | 2301230210100001010233 |
5 | 3100032014222413012 |
6 | 41545425315211531 |
7 | 2400141632054533 |
oct | 261544420010457 |
9 | 47211215457611 |
10 | 12211200201007 |
11 | 3988817193875 |
12 | 14527422a6ba7 |
13 | 6a7685261022 |
14 | 30304d3a5bc3 |
15 | 1629947ccd57 |
hex | b1b2440112f |
12211200201007 has 2 divisors, whose sum is σ = 12211200201008. Its totient is φ = 12211200201006.
The previous prime is 12211200200977. The next prime is 12211200201089. The reversal of 12211200201007 is 70010200211221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12211200201007 - 223 = 12211191812399 is a prime.
It is a super-3 number, since 3×122112002010073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211200201407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105600100503 + 6105600100504.
It is an arithmetic number, because the mean of its divisors is an integer number (6105600100504).
Almost surely, 212211200201007 is an apocalyptic number.
12211200201007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211200201007 is an equidigital number, since it uses as much as digits as its factorization.
12211200201007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 12211200201007 its reverse (70010200211221), we get a palindrome (82221400412228).
The spelling of 12211200201007 in words is "twelve trillion, two hundred eleven billion, two hundred million, two hundred one thousand, seven".
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