Base | Representation |
---|---|
bin | 1011000110110010010011… |
… | …0101100001100000110111 |
3 | 1121020101021020000110220221 |
4 | 2301230210311201200313 |
5 | 3100032024232030312 |
6 | 41545430310035211 |
7 | 2400142111455043 |
oct | 261544465414067 |
9 | 47211236013827 |
10 | 12211210033207 |
11 | 3988821799959 |
12 | 1452745648b07 |
13 | 6a76872c43b3 |
14 | 303050805023 |
15 | 1629955c1207 |
hex | b1b24d61837 |
12211210033207 has 2 divisors, whose sum is σ = 12211210033208. Its totient is φ = 12211210033206.
The previous prime is 12211210033171. The next prime is 12211210033223. The reversal of 12211210033207 is 70233001211221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12211210033207 - 227 = 12211075815479 is a prime.
It is a super-2 number, since 2×122112100332072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211210033507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105605016603 + 6105605016604.
It is an arithmetic number, because the mean of its divisors is an integer number (6105605016604).
Almost surely, 212211210033207 is an apocalyptic number.
12211210033207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211210033207 is an equidigital number, since it uses as much as digits as its factorization.
12211210033207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 12211210033207 its reverse (70233001211221), we get a palindrome (82444211244428).
The spelling of 12211210033207 in words is "twelve trillion, two hundred eleven billion, two hundred ten million, thirty-three thousand, two hundred seven".
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