Base | Representation |
---|---|
bin | 10001110001010000011… |
… | …111010111010000111111 |
3 | 11022201221000210201112122 |
4 | 101301100133113100333 |
5 | 130001324001023403 |
6 | 2332550355153155 |
7 | 154136343120305 |
oct | 21612037272077 |
9 | 4281830721478 |
10 | 1221121111103 |
11 | 43096903a513 |
12 | 1787b2ba57bb |
13 | 8b1c732539a |
14 | 43161686275 |
15 | 21b6e0ac838 |
hex | 11c507d743f |
1221121111103 has 2 divisors, whose sum is σ = 1221121111104. Its totient is φ = 1221121111102.
The previous prime is 1221121111099. The next prime is 1221121111141. The reversal of 1221121111103 is 3011111211221.
It is a weak prime.
It is an emirp because it is prime and its reverse (3011111211221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1221121111103 - 22 = 1221121111099 is a prime.
It is a super-2 number, since 2×12211211111032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221121111153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610560555551 + 610560555552.
It is an arithmetic number, because the mean of its divisors is an integer number (610560555552).
Almost surely, 21221121111103 is an apocalyptic number.
1221121111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221121111103 is an equidigital number, since it uses as much as digits as its factorization.
1221121111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1221121111103 its reverse (3011111211221), we get a palindrome (4232232322324).
The spelling of 1221121111103 in words is "one trillion, two hundred twenty-one billion, one hundred twenty-one million, one hundred eleven thousand, one hundred three".
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