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122113333102230 = 23252917465140491
BaseRepresentation
bin11011110000111110111001…
…110101111000011010010110
3121000100220212010211222222100
4123300332321311320122112
5112001201101233232410
61111414031335342530
734502253142154001
oct3360767165703226
9530326763758870
10122113333102230
11359aaa79059148
1211842470221a46
13531a312890282
142222461658538
15e1b6ac16b8c0
hex6f0fb9d78696

122113333102230 has 48 divisors (see below), whose sum is σ = 317603509623504. Its totient is φ = 32552392052160.

The previous prime is 122113333102087. The next prime is 122113333102237. The reversal of 122113333102230 is 32201333311221.

122113333102230 is a `hidden beast` number, since 1 + 2 + 2 + 11 + 333 + 310 + 2 + 2 + 3 + 0 = 666.

It is a super-2 number, since 2×1221133331022302 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 122113333102194 and 122113333102203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122113333102237) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 232307716 + ... + 232832775.

It is an arithmetic number, because the mean of its divisors is an integer number (6616739783823).

Almost surely, 2122113333102230 is an apocalyptic number.

122113333102230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

122113333102230 is an abundant number, since it is smaller than the sum of its proper divisors (195490176521274).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122113333102230 is a wasteful number, since it uses less digits than its factorization.

122113333102230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465143421 (or 465143418 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 122113333102230 its reverse (32201333311221), we get a palindrome (154314666413451).

The spelling of 122113333102230 in words is "one hundred twenty-two trillion, one hundred thirteen billion, three hundred thirty-three million, one hundred two thousand, two hundred thirty".

Divisors: 1 2 3 5 6 9 10 15 18 30 45 90 2917 5834 8751 14585 17502 26253 29170 43755 52506 87510 131265 262530 465140491 930280982 1395421473 2325702455 2790842946 4186264419 4651404910 6977107365 8372528838 13954214730 20931322095 41862644190 1356814812247 2713629624494 4070444436741 6784074061235 8140888873482 12211333310223 13568148122470 20352222183705 24422666620446 40704444367410 61056666551115 122113333102230