Search a number
-
+
12211530040132 = 2237191431991299
BaseRepresentation
bin1011000110110011011111…
…1010010000001101000100
31121020102002112011111220021
42301230313322100031010
53100033203142241012
641545522140544524
72400153045462613
oct261546772201504
947212075144807
1012211530040132
113988976398895
121452814852144
136a77086a87c7
1430308110587a
151629b3733007
hexb1b37e90344

12211530040132 has 24 divisors (see below), whose sum is σ = 22062659673600. Its totient is φ = 5909640956640.

The previous prime is 12211530040103. The next prime is 12211530040139. The reversal of 12211530040132 is 23104003511221.

It is a junction number, because it is equal to n+sod(n) for n = 12211530040097 and 12211530040106.

It is not an unprimeable number, because it can be changed into a prime (12211530040139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215967382 + ... + 216023917.

It is an arithmetic number, because the mean of its divisors is an integer number (919277486400).

Almost surely, 212211530040132 is an apocalyptic number.

It is an amenable number.

12211530040132 is a deficient number, since it is larger than the sum of its proper divisors (9851129633468).

12211530040132 is a wasteful number, since it uses less digits than its factorization.

12211530040132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 431991531 (or 431991529 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12211530040132 its reverse (23104003511221), we get a palindrome (35315533551353).

The spelling of 12211530040132 in words is "twelve trillion, two hundred eleven billion, five hundred thirty million, forty thousand, one hundred thirty-two".

Divisors: 1 2 4 37 74 148 191 382 764 7067 14134 28268 431991299 863982598 1727965196 15983678063 31967356126 63934712252 82510338109 165020676218 330041352436 3052882510033 6105765020066 12211530040132