Base | Representation |
---|---|
bin | 1011000110110011011111… |
… | …1010010000001101000100 |
3 | 1121020102002112011111220021 |
4 | 2301230313322100031010 |
5 | 3100033203142241012 |
6 | 41545522140544524 |
7 | 2400153045462613 |
oct | 261546772201504 |
9 | 47212075144807 |
10 | 12211530040132 |
11 | 3988976398895 |
12 | 1452814852144 |
13 | 6a77086a87c7 |
14 | 30308110587a |
15 | 1629b3733007 |
hex | b1b37e90344 |
12211530040132 has 24 divisors (see below), whose sum is σ = 22062659673600. Its totient is φ = 5909640956640.
The previous prime is 12211530040103. The next prime is 12211530040139. The reversal of 12211530040132 is 23104003511221.
It is a junction number, because it is equal to n+sod(n) for n = 12211530040097 and 12211530040106.
It is not an unprimeable number, because it can be changed into a prime (12211530040139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215967382 + ... + 216023917.
It is an arithmetic number, because the mean of its divisors is an integer number (919277486400).
Almost surely, 212211530040132 is an apocalyptic number.
It is an amenable number.
12211530040132 is a deficient number, since it is larger than the sum of its proper divisors (9851129633468).
12211530040132 is a wasteful number, since it uses less digits than its factorization.
12211530040132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 431991531 (or 431991529 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12211530040132 its reverse (23104003511221), we get a palindrome (35315533551353).
The spelling of 12211530040132 in words is "twelve trillion, two hundred eleven billion, five hundred thirty million, forty thousand, one hundred thirty-two".
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