Base | Representation |
---|---|
bin | 1011000110110101010101… |
… | …0011100011000011011111 |
3 | 1121020110100220011011001121 |
4 | 2301231111103203003133 |
5 | 3100040210420211312 |
6 | 41550043115151411 |
7 | 2400201214402342 |
oct | 261552523430337 |
9 | 47213326134047 |
10 | 12212023210207 |
11 | 39890a980a867 |
12 | 1452931a45567 |
13 | 6a778690bc12 |
14 | 3030ca800459 |
15 | 1629e1b9c707 |
hex | b1b554e30df |
12212023210207 has 2 divisors, whose sum is σ = 12212023210208. Its totient is φ = 12212023210206.
The previous prime is 12212023210159. The next prime is 12212023210291. The reversal of 12212023210207 is 70201232021221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12212023210207 - 211 = 12212023208159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212023211207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106011605103 + 6106011605104.
It is an arithmetic number, because the mean of its divisors is an integer number (6106011605104).
Almost surely, 212212023210207 is an apocalyptic number.
12212023210207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212023210207 is an equidigital number, since it uses as much as digits as its factorization.
12212023210207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12212023210207 its reverse (70201232021221), we get a palindrome (82413255231428).
The spelling of 12212023210207 in words is "twelve trillion, two hundred twelve billion, twenty-three million, two hundred ten thousand, two hundred seven".
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