Base | Representation |
---|---|
bin | 10001110001010101110… |
… | …010100010010011001111 |
3 | 11022202011020002220220021 |
4 | 101301111302202103033 |
5 | 130002014231214434 |
6 | 2333003253003011 |
7 | 154141502632102 |
oct | 21612562422317 |
9 | 4282136086807 |
10 | 1221210023119 |
11 | 430a04248419 |
12 | 178818923467 |
13 | 8b20c886048 |
14 | 4316d3cc739 |
15 | 21b76cc1cb4 |
hex | 11c55ca24cf |
1221210023119 has 2 divisors, whose sum is σ = 1221210023120. Its totient is φ = 1221210023118.
The previous prime is 1221210023081. The next prime is 1221210023153. The reversal of 1221210023119 is 9113200121221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1221210023119 is a prime.
It is a super-2 number, since 2×12212100231192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1221210023093 and 1221210023102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221210023219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610605011559 + 610605011560.
It is an arithmetic number, because the mean of its divisors is an integer number (610605011560).
Almost surely, 21221210023119 is an apocalyptic number.
1221210023119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221210023119 is an equidigital number, since it uses as much as digits as its factorization.
1221210023119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 1221210023119 in words is "one trillion, two hundred twenty-one billion, two hundred ten million, twenty-three thousand, one hundred nineteen".
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