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12212102200211 is a prime number
BaseRepresentation
bin1011000110110101101000…
…0000110111101110010011
31121020110120101210020222022
42301231122000313232103
53100040341130401321
641550055020202055
72400203163661034
oct261553200675623
947213511706868
1012212102200211
11398913a361161
12145295439932b
136a779a0a7674
143030d70c2a8b
151629e8aa1dab
hexb1b5a037b93

12212102200211 has 2 divisors, whose sum is σ = 12212102200212. Its totient is φ = 12212102200210.

The previous prime is 12212102200183. The next prime is 12212102200213. The reversal of 12212102200211 is 11200220121221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12212102200211 is a prime.

Together with 12212102200213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12212102200211.

It is not a weakly prime, because it can be changed into another prime (12212102200213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106051100105 + 6106051100106.

It is an arithmetic number, because the mean of its divisors is an integer number (6106051100106).

Almost surely, 212212102200211 is an apocalyptic number.

12212102200211 is a deficient number, since it is larger than the sum of its proper divisors (1).

12212102200211 is an equidigital number, since it uses as much as digits as its factorization.

12212102200211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 12212102200211 its reverse (11200220121221), we get a palindrome (23412322321432).

The spelling of 12212102200211 in words is "twelve trillion, two hundred twelve billion, one hundred two million, two hundred thousand, two hundred eleven".