Base | Representation |
---|---|
bin | 10110101111110010… |
… | …11110101111010011 |
3 | 1011112002020011112121 |
4 | 23113321132233103 |
5 | 200002244313042 |
6 | 5335443435111 |
7 | 611425113115 |
oct | 132771365723 |
9 | 34462204477 |
10 | 12212104147 |
11 | 51a7461661 |
12 | 2449985a97 |
13 | 11c8099339 |
14 | 83bc713b5 |
15 | 4b71bb367 |
hex | 2d7e5ebd3 |
12212104147 has 2 divisors, whose sum is σ = 12212104148. Its totient is φ = 12212104146.
The previous prime is 12212104129. The next prime is 12212104193. The reversal of 12212104147 is 74140121221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12212104147 - 231 = 10064620499 is a prime.
It is not a weakly prime, because it can be changed into another prime (12212108147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106052073 + 6106052074.
It is an arithmetic number, because the mean of its divisors is an integer number (6106052074).
Almost surely, 212212104147 is an apocalyptic number.
12212104147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212104147 is an equidigital number, since it uses as much as digits as its factorization.
12212104147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 12212104147 its reverse (74140121221), we get a palindrome (86352225368).
The spelling of 12212104147 in words is "twelve billion, two hundred twelve million, one hundred four thousand, one hundred forty-seven".
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