Base | Representation |
---|---|
bin | 11011110001000110111101… |
… | …100011000101111000111111 |
3 | 121000101202012010100010111112 |
4 | 123301012331203011320333 |
5 | 112001321311204021114 |
6 | 1111422022052312235 |
7 | 34503010432021421 |
oct | 3361067543057077 |
9 | 530352163303445 |
10 | 122121985220159 |
11 | 35a03708a41431 |
12 | 1184408591267b |
13 | 531b091249392 |
14 | 2222a42794811 |
15 | e1ba16a2c13e |
hex | 6f11bd8c5e3f |
122121985220159 has 2 divisors, whose sum is σ = 122121985220160. Its totient is φ = 122121985220158.
The previous prime is 122121985220119. The next prime is 122121985220161. The reversal of 122121985220159 is 951022589121221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122121985220159 - 232 = 122117690252863 is a prime.
It is a super-2 number, since 2×1221219852201592 (a number of 29 digits) contains 22 as substring.
Together with 122121985220161, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122121985220119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61060992610079 + 61060992610080.
It is an arithmetic number, because the mean of its divisors is an integer number (61060992610080).
Almost surely, 2122121985220159 is an apocalyptic number.
122121985220159 is a deficient number, since it is larger than the sum of its proper divisors (1).
122121985220159 is an equidigital number, since it uses as much as digits as its factorization.
122121985220159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 50.
The spelling of 122121985220159 in words is "one hundred twenty-two trillion, one hundred twenty-one billion, nine hundred eighty-five million, two hundred twenty thousand, one hundred fifty-nine".
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